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-7+12x=-10x^2
We move all terms to the left:
-7+12x-(-10x^2)=0
We get rid of parentheses
10x^2+12x-7=0
a = 10; b = 12; c = -7;
Δ = b2-4ac
Δ = 122-4·10·(-7)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{106}}{2*10}=\frac{-12-2\sqrt{106}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{106}}{2*10}=\frac{-12+2\sqrt{106}}{20} $
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